Shell Programming and Scripting

Varialbes

NOTIFY="No"

#Check if the slaves are running

SLAVE="$(mysql -uroot -e 'show slave status \G;' | egrep "Slave_IO_Running|Slave_SQL_Running" | awk -F "[:]" '{ print $2 }' | cut -d, -f1)"

Yes
Yes

#Compare SLAVE to Notify

if (("$SLAVE" > "$NOTIFY)); then

#IT should stop the slave

mysql -uroot -e'stop slave;'

but the problem is that my output for SLAVE is two lines

Yes
Yes

Now it seems like it doesnt recognizes the output of SLAVE when comparing to NOTIFY

Now how will i do that it will matches the YES to No.

TOmake it clear here's how i want the script to work

1. Check the status of slave by getting the Slave_IO_Running and Slave_IO_Running if it is in YES state.
Code:
mysql -uroot -e 'show slave status \G;' | egrep "Slave_IO_Running|Slave_SQL_Running" | awk -F "[:]" '{ print $2 }' | cut -d, -f1
Yes
Yes

Slave_IO_Running: Yes
Slave_SQL_Running: Yes

2. IF the status is YES then it will compare to notify and do nothing
Code:
if (("$SLAVE" == "$NOTIFY)); then

But if it matches with NO then it will run the next command which is

Code:
mysql -uroot -e 'stop slave';


Now the problem is it seems like it SLAVE and NOTIFY is not comparing correctly.

Please help me guys to fix this.

thanks

Do not post classroom or homework problems in the main forums. Homework and coursework questions can only be posted in this forum under special homework rules.

Please review the rules, which you agreed to when you registered, if you have not already done so.

More-than-likely, posting homework in the main forums has resulting in a forum infraction. If you did not post homework, please explain the company you work for and the nature of the problem you are working on.

If you did post homework in the main forums, please review the guidelines for posting homework and repost.

Thank You.

The UNIX and Linux Forums.