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parsing argument in perl


 
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# 1  
Old 08-31-2011
parsing argument in perl

in bash:

HTML Code:
LIST=`cat $1`

for i in $LIST
do
  ...
done
how will i do this in perl ?

$1 is my first arguement. I'm a newbie in perl and will appreciate much your help guys ...

Last edited by linuxgeek; 08-31-2011 at 09:59 AM..
# 2  
Old 08-31-2011
Code:
while (<>) {
  chomp; split;
  foreach $i (@_) {
    ...
  }
}

If you want to get more familiar with perl, in any case it is recommendable to study the man pages (which in case of perl are very instructive), the most basic ones are:
perlrun, perlsyn, perldata, perlop, perlfunc (second level: perlsub, perlre, perlvar)
This User Gave Thanks to hfreyer For This Post:
# 3  
Old 08-31-2011
Code:
perl -E 'say for @ARGV' 1 'a b' --
1
a b
--

This User Gave Thanks to yazu For This Post:
# 4  
Old 08-31-2011
hi hfreyer,

do you mean its like this ?

Code:
while ($ARGV[0]) {   
chomp; split;   
foreach $i (@_) {
   ...   
   }
}

how will i call my arguement1 ?
# 5  
Old 08-31-2011
If you want just parse your arguments:
Code:
for my $arg (@ARGV) {
  # no split, no chomp
  # do what you want with your $arg-s
}

If you want to do something with lines from the file from your first argument:
Code:
open my $fd, "<", "$ARGV[0]";
while (<$fd>) {
  # the lines go into $_
  # so do something with $_
  # you can remove the newline
  chomp;
  # split it in an array
  my @fields = split;  # shortcut for split(/\s+/, $_)
}
close $fd;


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