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Replace string in vi

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# 1  
Old 08-24-2011
Replace string in vi
Hello,
Need vi script.
file:
Code:
dog1!cat!
dog2!bird!
dog1!fish!
dog2!lion!
...

expected:
Code:
dog1!bird!
dog2!NULL!
dog1!lion!
dog2!NULL!
...

Need replace from dog2!"word"! to dog1!"word"! and write in dog2!NULL! and the same logic for all strings where are dog1 and dog2

Any idea?

thanks
Last edited by pludi; 08-24-2011 at 05:24 AM..
# 2  
Old 08-24-2011
In the ":" mode:
Code:
%s/dog2!.*/dog2!NULL!/

# 3  
Old 08-24-2011
Quote:
Originally Posted by bartus11
In the ":" mode:
Code:
%s/dog2!.*/dog2!NULL!/

with your script result are:
dog1!cat!
dog2!NULL!
dog1!fish!
dog2!NULL!

but my expected result are from:
dog1!cat!
dog2!bird!
dog1!fish!
dog2!lion!
...
to:
dog1!bird!
dog2!NULL!
dog1!lion!
dog2!NULL!
...
do you see differences?

thanks
# 4  
Old 08-24-2011
Try:
Code:
%s/dog1.*\ndog2!\(.*\)/dog1!\1\rdog2!NULL!/

Last edited by bartus11; 08-24-2011 at 05:40 AM..
This User Gave Thanks to bartus11 For This Post:
aaruncee
# 5  
Old 08-24-2011
Quote:
Originally Posted by bartus11
Try:
Code:
%s/dog1.*\ndog2!\(.*\)/dog1!\1\rdog2!NULL!/


Results:
dog1!cat!
dog2!bird!
dog1!fish!
dog2!lion!

substitute pattern match failed

Any idea?
Last edited by aaruncee; 08-24-2011 at 06:41 AM..
# 6  
Old 08-24-2011
I guess you are using original "vi", not "vim" on which I tested this command... Does it have to be done in vi? If not, you can try something like this:
Code:
perl -p0e 's/dog1.*\ndog2(.*)/dog1\1\ndog2!NULL!/g' file

This User Gave Thanks to bartus11 For This Post:
aaruncee
# 7  
Old 08-24-2011
Quote:
Originally Posted by bartus11
I guess you are using original "vi", not "vim" on which I tested this command... Does it have to be done in vi? If not, you can try something like this:
Code:
perl -p0e 's/dog1.*\ndog2(.*)/dog1\1\ndog2!NULL!/g' file


Yes, it have to be done in vi.

thanks
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