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Removing duplicate records in a file based on single column

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# 1  
Old 08-20-2011
Data Removing duplicate records in a file based on single column
Hi,

I want to remove duplicate records including the first line based on column1. For example

inputfile(filer.txt):
-------------
Code:
1,3000,5000
1,4000,6000
2,4000,600
2,5000,700
3,60000,4000
4,7000,7777
5,999,8888

expected output:
----------------
Code:
3,60000,4000
4,7000,7777
5,999,8888

Is it possible to achieve this using awk command ??

I tried below awk command , it is working but i dont want to give two times file name(filer.txt) in the command. I am allowed to give file name only one time.
Code:
awk -F"," 'NR == FNR {  cnt[$1] ++} NR != FNR {  if (cnt[$1] == 1) print $0 }' filer.txt filer.txt

Please suggest me how to achieve this.

Thanks in advance
Last edited by Franklin52; 08-22-2011 at 03:57 AM.. Reason: Please use code tags for code and data samples, thank you
# 2  
Old 08-20-2011
Use the unique option of the sort command.
Sort the file using the unique option. Then use diff between the original and the output (of the sort) file. Then use the diff file to remove the records from the output file of the sort.
# 3  
Old 08-20-2011
Thanks for reply jgt Smilie, i am allowed to use awk/sed command alone Smilie. can someone give suggestion how exactly i can code it in single command line.



Quote:
Originally Posted by jgt
Use the unique option of the sort command.
Sort the file using the unique option. Then use diff between the original and the output (of the sort) file. Then use the diff file to remove the records from the output file of the sort.
# 4  
Old 08-20-2011
Quote:
Originally Posted by G.K.K
i am allowed to use awk/sed command alone Smilie. can someone give suggestion how exactly i can code it in single command line.
Who makes up these rules, and why????
# 5  
Old 08-20-2011
Got solution using single line command. Thanks. Problem resolved Smilie

Quote:
Originally Posted by jgt
Who makes up these rules, and why????
# 6  
Old 08-20-2011
Hi,

One solution using 'sed':
Code:
$ cat infile
1,3000,5000
1,4000,6000
2,4000,600
2,5000,700
3,60000,4000
4,7000,7777
5,999,8888
$ sed -ne '$! { /\n/! N; } ; :a ; $! { /^\([0-9]*\),.*\n\1[^\n]\+$/ { N; ba; }; } ; s/^\([0-9]*\),.*\n\1// ; tb ; P ; D ; :b ; D' infile
3,60000,4000
4,7000,7777
5,999,8888

Regards,
Birei
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