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Shell Programming and Scripting

Grep syntax print after certain character

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Top Forums Shell Programming and Scripting Grep syntax print after certain character
# 8  
Old 08-17-2011
Code:
$ awk -F"[:=]" '{if($0~/Time/){printf("\"%s:%s:%s\"\n",$2,$3,$4)}else{printf("\"%s\",",$2)}}' test.txt 
" Ron Mexico"," Michael Vick"," Mike_Vick_2011.bat"," 11.82"," 6/13/2011 10:29:27 AM"

---------- Post updated at 08:39 PM ---------- Previous update was at 08:31 PM ----------

you dont need to use grep and pipe this awk. You can try the below.

Code:
awk -F"[:=]" ' /packaged by/ || /employee/ || /file name/ || /Total Data/|| /Begin Time/ {if($0~/Time/){printf("\"%s:%s:%s\"\n",$2,$3,$4)}else{printf("\"%s\",",$2)}}' log.txt

# 9  
Old 08-17-2011
How do you remove the space after any "="?

Something like?
Code:
awk -F"[':' '= ']"

---------- Post updated at 01:42 PM ---------- Previous update was at 01:21 PM ----------

Is this going to work for all files in a directory?

This will parse the first file, but not work on other log files in the directory:
Code:
awk -F"[:=]" ' /packaged by/ || /employee/ || /file name/ || /Total Data/|| /Begin Time/ {if($0~/Time/){printf("\"%s:%s:%s\"\n",$2,$3,$4)}else{printf("\"%s\",",$2)}}' /path/to/*
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