Shell Programming and Scripting

Hello;

I need to generate a csv file that contains a list of all the files in a particular server (from the root directory ie: \) that have a permission stamp of 777. I would like to create the csv so that it contains the following:

server name, file name, full path name where file exists, owner of file, group file belongs too

I am aware of the commands to get this information at the prompt or even spit it out via a script; what I do not know is how to read the information from each command and create a csv file.

Help would be graciously appreciated.

Thanks
G

try this... you may have to format the output... also "find" command has option to specify the permission during search... good luck!

Code:

find . | xargs stat

regards,
Ahamed

This should work:

Code:

hname=$(hostname)
find / -type f -perm 777 -ls | \
while read a b c d user group e f g h file
do
    echo "$hname;$(basename "$file");$(dirname "$file");$user;$group"
done

It can be more efficient without running basename and dirname, if you are running ksh/bash. That will avoid a lot of 'forking' if you are running through a lot of files.

Code:

echo "$hname;${file##*/};${file%/*};$user;$group"

Just some more info I should have added .... not using BASH or KSH, just CSH...OS is HP-UX. Hope this helps.

Pludi
When I ran the command "find / -type f -perm 777 -ls | \ " at the prompt to see what it would do; I get a return for a new line; see below:

[dslgvol@pike ./]$ find / -type f -perm 777 -ls | \
>

That new line is expected. The \ tells the shell that command continues on next line. Please run the entire set of code that pludi gave above.

Pludi:
When I try and run it with a script I get:

Code:

[dslgvol@pike ./dslgvol]$ sh testscript.sh
find: bad option -ls
[dslgvol@pike ./dslgvol]$