Using AWK in a bash script

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# 1  
Old 08-01-2011
Using AWK in a bash script

So I am a newbie obviously but I need some help.

I am trying to run a script to check that the number of fields in a database is equal to 4, if not they should try again and run an appropriate database file. The fields are separated by a semi colon. I've tried a lot of things, this what I'm trying to fix

awk -F':' { if (NF != 4){
        zenity --info --text "The file pathname \"$2\" is not a four  field colon separated database file.\n\nClick OK to exit, and re-run  this program."
} \"$2\"

Last edited by radoulov; 08-01-2011 at 06:29 PM.. Reason: Code tags.
# 2  
Old 08-01-2011
Don't you need something so the zenity line runs as a shell not awk command?
# 3  
Old 08-01-2011
awk -F':' 'NF!=4{
    cmd="zenity --info --text '\''The file pathname \"" file "\" is not a four  field colon separated database file.\n\nClick OK to exit, and re-run this program.'\''";
    print ""|cmd
}' file=$2 $2

Last edited by neutronscott; 08-01-2011 at 08:58 PM..
# 4  
Old 08-02-2011
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