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[SCRIPT] read and substitution

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# 1  
Old 07-29-2011
[SCRIPT] read and substitution
Hi all,

Actually I have a huge bash file like:

Code:
port1=$PORT && if [ $port -eq "$NUM"]; then .....
....stuff
port2=$PORT && if [ $port -eq "$NUM"]; then .....
...stuff
port3=$PORT && if [ $port -eq "$NUM"]; then .....
...stuff
port4=$PORT && if [ $port -eq "$NUM"]; then .....
...stuff
port5=$PORT && if [ $port -eq "$NUM"]; then .....

I would like to change the $port inside the square brackets accordly to the beginning of line, by getting:


Code:
port1=$PORT && if [ $port1 -eq "$NUM"]; then .....
....stuff
port3=$PORT && if [ $port3 -eq "$NUM"]; then .....
...stuff
port8=$PORT && if [ $port8 -eq "$NUM"]; then .....
...stuff
port66=$PORT && if [ $port66 -eq "$NUM"]; then .....
...stuff
port5=$PORT && if [ $port5 -eq "$NUM"]; then .....

I was thinking to do that with sed but not able to work out a solution.
Any idea please?
Thanks in advance
# 2  
Old 07-29-2011
Code:
$ nawk -F"[= ]" ' {if($1~/port/) {$6="\$"$1; print $0} else {print $0}} ' test                                                                     
port1 $PORT && if [ $port1 -eq "$NUM"]; then .....
....stuff
port2 $PORT && if [ $port2 -eq "$NUM"]; then .....
...stuff
port3 $PORT && if [ $port3 -eq "$NUM"]; then .....
...stuff
port4 $PORT && if [ $port4 -eq "$NUM"]; then .....
...stuff
port5 $PORT && if [ $port5 -eq "$NUM"]; then .....

This User Gave Thanks to itkamaraj For This Post:
Dedalus
# 3  
Old 07-29-2011
Thanks a lot
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