How to retrieve a file from specific path using unix script?


 
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# 1  
Old 07-23-2011
How to retrieve a file from specific path using unix script?

Hi i'm new to shell script,
i want to get the filename from specific location which i mentioned in my script.
The scirpt should read the filename exactly using the following command "ls -ltr | tail -1".

Could someone show me on this. Below is my script
Code:
#!/bin/ksh
PATH=  /usr/
if [ -d $PATH ]
then
  echo "is a directory"
  filename = $ls -ltr | tail -1
fi


Last edited by Franklin52; 07-23-2011 at 10:01 AM.. Reason: Please use code tags for data and code samples, thank you
# 2  
Old 07-23-2011
???

It's impossible to understand what you want (for me at least).
# 3  
Old 07-23-2011
Don't use spaces around the "=" sign:
Code:
#!/bin/ksh
PATH=/usr/
if [ -d $PATH ]
then
  echo "is a directory"
  filename=$(ls -ltr | tail -1)
fi

# 4  
Old 07-23-2011
Hi,

Thanks for your reply.

What i exactly required is, i need to write a shell script which list the latest file from the path (ex: /www/a/temp/in/) and i want to reterive the contents of that latest file into a variable defined inside my shell script. (ex: filename).

I'm running my script in the location (/www/a/).

Code:
#!/bin/ksh
PATH= /www/a/temp/in/
if [ -d $PATH ]
then
#it should copy the contents of latest file in the specified path into a variable, say for example filename
fi

Please help me on this.

Thanks for your help in advance

Last edited by radoulov; 07-23-2011 at 12:06 PM.. Reason: Coda tags!
# 5  
Old 07-24-2011
MySQL

hi,

You have specified your target directory different from the directory in which script is present...


Code:
#!/bin/ksh
PATH=/full/path/to/your/target/directory
cd $PATH   #go in that directory
filename=$( ls -lrt | tail -1 | awk '{print $7}') #variable contains name of latest file
file_content=$(cat $filename) #this variable contains content of that file...
echo $file_content #to see the output

#your code.....=>
if [ -d $PATH ]    # I didn't understand your purpose of checking the directory here...
then
  echo "is a directory"
  filename=$(ls -ltr | tail -1)
fi


Regards,
ironmonkey... Smilie
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