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Variable inside AWK printf

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# 1  
Old 07-09-2011
Variable inside AWK printf
Hi,

Is it possible to print a variable inside awk printf ??

Quote:
nawk -v date="2011" ' BEGIN {FS=","} {printf("%-1s%-4s%2s%-4s","0",$2,date,$3)}'
the above is not working
# 2  
Old 07-09-2011
What is the problem ?
The statement seems valid.


Jean-Pierre.
# 3  
Old 07-09-2011
Am sorry when i give more than one variable am getting an error

Code:
 
cat $FILENAME |grep ^1 | while read line
do
echo "$line" | nawk -v FD="$F_D" SS="$S_S" DS="$D_S" 'BEGIN {FS=","} {printf("%-1s%-4s%-30s","0",$2,FD,SS,DS)}' >> HEAD
done

ERROR

HTML Code:
+ read line
+ cat testf
+ grep ^1
+ nawk -v FD=ALPHARMA_JDE                   SS=JDE_BRIDGE      DS=COMPUTRON    BEGIN {FS=","} {printf("%-1s%-4s%-30s","0",$2,FD,SS,DS)}
+ echo 1,2011,07,99999
+ 1>> HEAD
nawk: can't open file BEGIN {FS=","} {printf("%-1s%-4s%-30s","0",$2,FD,SS,DS)}
 source line number 1
+ read line
# 4  
Old 07-09-2011
1) Add -v options
Code:
nawk -v FD="$F_D" -v SS="$S_S" -v DS="$D_S" 'BEGIN {FS=","} {printf("%-1s%-4s%-30s","0",$2,FD,SS,DS)}'

2) Remove loop (cat,grep while read) :
Code:
nawk -v FD="$F_D" -v SS="$S_S" -v DS="$D_S" 'BEGIN {FS=","} /^1/ {printf("%-1s%-4s%-30s","0",$2,FD,SS,DS)}' $FILENAME

Jean-Pierre.
This User Gave Thanks to aigles For This Post:
selvankj
# 5  
Old 07-09-2011
When specifying multiple variables, you need to put -v in front of each of them:
Code:
nawk -v FD="$F_D" -v SS="$S_S" -v DS="$D_S" 'BEGIN {FS=","} {printf("%-1s%-4s%-30s","0",$2,FD,SS,DS)}'

This User Gave Thanks to bartus11 For This Post:
selvankj
# 6  
Old 07-09-2011
Thank you all... I have one more question
When i sum up the values of a column, i get the total in exponent, is it possible to convert in to a round fingure with 2 decimal places ?

Code:
awk -F, '{value=$28 ;if(value>0) {credit+=value}} END {print credit} ' joegtest_0705.txt

Code:
 
Output
1.20994e+07

# 7  
Old 07-09-2011
Use printf "%.2f",credit in the END section.
This User Gave Thanks to bartus11 For This Post:
selvankj
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