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Find/Replace in XML file


 
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# 1  
Find/Replace in XML file

I am not sure how to approach this find/replace using a shell script. Any help or guidance appreciated.

I want to find this:

Code:
<objects/>
<thumb>thumb_0001.jpg</thumb>
<preview>preview_0001.jpg</preview>

And replace with something like this:

Code:
<objects>
<link>preview_0001.html</link>
</objects>
<thumb>thumb_0001.jpg</thumb>
<preview>preview_0001.jpg</preview>

I cant figure out how to make my replacement string include part of what i found, since i want the name of the html to be the name of the preview image. Is this possible with sed or awk?
# 2  
something like:

Code:
#  nawk -F"[_.]" '!/thumb/{print} /thumb/{print "<link>preview_"$2".html</link>"; print "</objects>";print}' infile
<objects/>
<link>preview_0001.html</link>
</objects>
<thumb>thumb_0001.jpg</thumb>
<preview>preview_0001.jpg</preview>

what you're after ?
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