Shell Programming and Scripting

Hi!
I think my last post was a little confusing, so I will try an post a sample this time.
I have a script which is supposed to output two columns of a file to a different file, then take the first column, search a directory for it, and replace anything it finds with the second column. This is what I have:

Code:

for file in /XXXX/XXXX/XXXX/I
do
     echo $VAR|awk '{printf "%d\n",$1}'|read NEWVAR
done

awk < XXXX_table.txt '{print $1 $3}' >> var1

for line in /XXXX/XXXX/XXXX/var1
do
    x=$(awk < var1 '{print $1}') 
    y=$(awk < var1 '{print $2}')
    cd /XXXX/XXXX/XXXX/I
    sed "s/$x/$y/g"
    echo $x
    echo $y
done

The first loop is supposed to remove all of the leading zeroes in all the files in that directory as well, but I guess that is wrong too.

Having lots of difficulty on this one, but I feel as though the answer is very simple

Perhaps you would be good enough to explain to us what difficulty you are having?

Actually now it is just the command to remove leading zeroes from all filenames in a directory.

They look like this:

Code:

XXX03XXX.00XXXXXXX.XXXXXXXX

And I want to remove just the leading zeroes on the second string if they exist. I have been trying to use this with no success.

Code:

echo $VAR|awk '{printf "%d\n",$1}'|read NEWVAR

Hi

Fire this below command in the directory in which you want to rename:

Code:

$ for i in *
do
mv $i `echo $i | sed 's/\.0*/./'`
done

Guru.

Excellent! that is perfect.
And one last thing! I am trying to replace one variable (string) with antoher variable using:

Code:

sed "s/$x/$y/g"

however, it seems as though this is incorrect, as it makes a new directory.