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# 1  
Old 06-29-2011
grep for a particular field
Hi All,

I have the following in a text file

Code:
#---- Set Silent License Acceptance
#---- Accept license agreement: remove # sign
#----                 example: LICENSE_ACCEPTED=true
#---- if the LICENSE_ACCEPTED is anything other then true the installation will exit
#----        no log will be produced, no indication of failure provided
#----
#---- By removing the # sign before #LICENSE_ACCEPTED=false and changing false to true
#---- you have signified acceptance of the Netcool/Impact 5.1.1 license agreement
#LICENSE_ACCEPTED=false

I want to grep only the LICENSE_ACCEPTED=false alone. The LICENSE_ACCEPTED=false is present at the bottom I don't want to grep anything in the middle and this LICENSE_ACCEPTED=false has a '#' symbol also. So, how to grep this part alone

I am actually grepping this field and making false to true by using the following command but the current command greps all the LICENSE_ACCEPTED

Code:
echo "`grep -q LICENSE_ACCEPTED $NCHOME/installSilent_response.txt && sed 's#LICENSE_ACCEPTED=[^ ]*#LICENSE_ACCEPTED='${RESPONSE}#g'' $NCHOME/installSilent_response.txt || sed '$ a LICENSE_ACCEPTED='${RESPONSE}' $NCHOME/installSilent_response.txt'`" >> $NCHOME/installSilent_response_hp.txt

So,

1. how to remove the # from the legal unique LICENSE_ACCEPTED
2. And then just grep the unique LICENSE_ACCEPTED

Thanks for any help
Dinesh
# 2  
Old 06-29-2011
???
Code:
grep '^#LICENSE_ACCEPTED=false'

or
Code:
tail -1

# 3  
Old 06-29-2011
Code:
$ cat temp
#---- Set Silent License Acceptance
#---- Accept license agreement: remove # sign
#----                 example: LICENSE_ACCEPTED=true
#---- if the LICENSE_ACCEPTED is anything other then true the installation will exit
#----        no log will be produced, no indication of failure provided
#----
#---- By removing the # sign before #LICENSE_ACCEPTED=false and changing false to true
#---- you have signified acceptance of the Netcool/Impact 5.1.1 license agreement
#LICENSE_ACCEPTED=false



with grep
Code:
cat temp | tail -1 | grep -o "LICENSE_ACCEPTED=false"

with awk
Code:
cat temp | tail -1 | awk -F "#" '{print $2}'

with sed
Code:
cat temp | tail -1 | sed 's/#//'

Last edited by Franklin52; 06-29-2011 at 09:44 AM.. Reason: Please use code tags for code and data samples, thank you
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