Need to extract a folder from a full path


 
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# 1  
Old 06-28-2011
Need to extract a folder from a full path

Hi everyone,

I have different folders which looks like this:

/mnt/ecrm/master/ecrm/templates/brochure/de_DE/zeitlos.ott
/mnt/ecrm/master/ecrm/templates/mail/en_US/default.html
/templates/header_and_footer/en_US/default.txt

I want to get the bold text only in a variable. I already have a regex prepared:
(\w+(?=\/\w+_\w)) => Get me the word before /anyword_anyword (here: de_DE or en_US)

But I don't know how the implement that into a bash shell script. I tried sed, which doen't support advanced regex and I am too stupid for awk.

Help?Smilie
# 2  
Old 06-28-2011
With GNU Sed
Code:
sed 's|.*/\([^/]*\)/[A-Za-z_]*/.*$|\1|' inputfile > outfile

# 3  
Old 06-28-2011
Another one with awk:
Code:
awk -F"/" '{print $(NF-2)}' infile

# 4  
Old 06-28-2011
Thank you guys.
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