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Unix script required

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# 8  
Old 06-17-2011
Quote:
Originally Posted by itkamaraj
Code:
 
bash-3.00$ !sed
sed -n 's/^.*=\(.\)/\1/p' test
1
2
3
214
bash-3.00$ cat test
aasaasas=1
bsasasasasa=2
sawqas=3
abc=214

your command gives the correct ouput.

Code:
 
bash-3.00$ sed 's/.*=//' test
1
2
3
214

itkamaraj, could you explain, what is that mean? I really want to know about regex.
# 9  
Old 06-17-2011
* (star)Repeats the previous item zero or more times. Greedy, so as many items as possible will be matched before trying permutations with less matches of the preceding item, up to the point where the preceding item is not matched at all
Regular Expressions Reference - Basic Syntax

.*= this will match the aasaasas=, bsasasasasa=, ..........

so i am replacing that with empty sed 's/.*=//'
This User Gave Thanks to itkamaraj For This Post:
franzramadhan
# 10  
Old 06-17-2011
How do we do it with Cut.
# 11  
Old 06-17-2011
Quote:
Originally Posted by itkamaraj
Code:
 
bash-3.00$ !sed
sed -n 's/^.*=\(.\)/\1/p' test
1
2
3
214
bash-3.00$ cat test
aasaasas=1
bsasasasasa=2
sawqas=3
abc=214

your command gives the correct ouput.

Code:
 
bash-3.00$ sed 's/.*=//' test
1
2
3
214


How do you achieve the same with Cut.
# 12  
Old 06-17-2011
Ok thanks for your explanation.
# 13  
Old 06-17-2011
did u try with cut ?

did u read the man page of cut ?

read about the -d in the cut command
# 14  
Old 06-17-2011
try this
Code:
 
awk -F\= '{print $NF}' 123.txt
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