Shell Programming and Scripting

Hi.

I have a text file with lines like this:

Code:

( chp_testfile_0065 "Blablabla." )
( chp_testfile_0003 "Blablabla" )
( chp_testfile_0123 "Blablabla" )

I need one more 0 in each line, so that I have 5 digits in a sequence. I also need an ongoing numeration from 1 to n, so that

Code:

( chp_testfile_00001 "Blablabla." )
( chp_testfile_00002 "Blablabla" )
( chp_testfile_00003 "Blablabla" )

Does anyone have an idea how I can accomplish this?

I have a php script, which once did that for me..but with different positions...but I don't know php at all and don't understand it, so I can't rewrite it to suit my needs. I could copy and paste it if that helps!

Thanks,

Kat

Try:

Code:

perl -pe '$j=sprintf "%05d",++$i;s/\d+ "/$j "/' file

Thanks! How would I do this, if I don't want the numeration to start from 1, but from e.g. 14000?

Code:

perl -pe 'BEGIN{$i=14000};$j=sprintf "%05d",$i++;s/\d+ "/$j "/' file

Thank you :-)

I was trying to use the same code for a similar textfile, which doesn't have the double quotes, so:

( chp_testfile_0065 Blablabla. )
( chp_testfile_0003 Blablabla )
( chp_testfile_0123 Blablabla )

But it didn't work. Is there a way this code can be adjusted?

This should do.

Code:

 
perl -pe '$j=sprintf "%05d",++$i;s/\d+ /$j /'