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separating part of code from the program

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Top Forums Shell Programming and Scripting separating part of code from the program
# 8  
Old 06-12-2011
Code:
kent$  awk -F',' 'NR==FNR{for(i=1;i<=NF;i++)a[$i]=1}NR>FNR{for(i=1;i<=NF;i++)if($i in a)print $i}' 1.txt 2.txt
a
c

This User Gave Thanks to sk1418 For This Post:
aruna t
# 9  
Old 06-12-2011
MySQL
Quote:
Originally Posted by sk1418
assume that your file is called t.txt, and each function has only one (the last one closing the function) "}":

Code:
 sed -r 's/\}/\}-----/g' t.txt|awk 'BEGIN{FS="-----";RS=""} {for (i=1;i<NF;i++){print $i > "file"i".txt"}} '

the command above will generate 3 files: file1-3.txt.

Hi! But consider the program "prog1.c" which I've attached..
If I execute the query, I need to get 4 files, ie file1.txt-file4.txt, but I'm getting 7 files file1.txt-file7.txt.
Please check out the zip file which I've attached..
Why is that so?
prog1.zip (2.1 KB) 
# 10  
Old 06-12-2011
Originally Posted by sk1418 Image
assume that your file is called t.txt, and each function has only one (the last one closing the function) "}":
This User Gave Thanks to sk1418 For This Post:
aruna t
# 11  
Old 06-12-2011
Oh yes.. Thanks.. but is there any other way to separate out for such kind of programs??
# 12  
Old 06-12-2011
based on the content in your prog1.c:
Code:
sed -r 's/^(void|int) .*\(\)$/-----&/g' t.txt |awk 'BEGIN{FS="-----";RS=""} {for (i=1;i<=NF;i++){print $i > "file"i".txt"}} '

will generate four files. file1-4.txt.
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