Job Runtimes by AWK


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# 1  
Job Runtimes by AWK

Hi ,

I need to find runtime of jobs.

I have written below script to get start and end times for a list of jobs.

Code:
#!/bin/bash
 
InputFile_Name=/var/tmp/cgk/pre2_oper_status_7amcheck_jobs
if [ ! -f $InputFile_Name  ]
then
  echo "File: $InputFile_Name  doesn't exist , Pls check & run again"
  echo "Exiting the script"
  exit 1;
fi
while read Job_Name
do
  if [ ! -z $Job_Name ]
  then
        len=`echo $Job_Name | awk  '{print length }'`
          if [ $len -ge 24 ]
          then
                autorep -j $Job_Name  -w | grep -i $Job_Name |  awk '{ print $1 "\t\t\t\t   " $2 " " $3 " " $4 " " $5 " " $6 }'
          else
                autorep -j $Job_Name  -w | grep -i $Job_Name |  awk '{ print $1 "\t\t\t\t\t\t " $2 " " $3 " " $4 " " $5 " " $6 }'
          fi
  else
     echo ""
  fi
done  < $InputFile_Name
echo ""
exit 0

Output :--

Code:
jobname1        04/06/2011 09:33:37 04/06/2011 09:34:04 SU
jobname2        04/06/2011 09:51:33 04/06/2011 10:02:28 SU
jobname3        04/06/2011 09:51:37 04/06/2011 10:08:56 SU


I am trying to use script in below link

https://www.unix.com/shell-programmin...g-entries.html

But i am not able to get the run times of each job in HH:MIN:SEC

Can some one assist on this to get run times of each job.
# 2  
The awk you have referred uses different format, try this one,
Code:
user@tioman> (/home/user) $ cat time.awk
{
split($2,sdate,"/")
split($3,stime,":")
split($4,edate,"/")
split($5,etime,":")

s_secs=mktime(sdate[3]" "sdate[2]" "sdate[1]" "stime[1]" "stime[2]" "stime[3])

e_secs=mktime(edate[3]" "edate[2]" "edate[1]" "etime[1]" "etime[2]" "etime[3])

print $1,strftime("%T",e_secs-s_secs)


}
You have new mail in /var/spool/mail/user
user@tioman> (/home/user) $ awk -f time.awk test.txt
bname1 07:30:27
jobname2 07:40:55
jobname3 07:47:19
user@tioman> (/home/user) $

I have a different time zone set here, so my output has 7 hrs 30 mins plus in each one.

please post your output as well.
# 3  
Job Runtimes by AWK

Hi Kumaran,

Instead of writing awk script is there any way we can do on the command line like i am able to print other columns. ??
awk '{ print $1 "\t\t\t\t " $2 " " $3 " " $4 " " $5 " " $6 }'
# 4  
Taking time difference isn't easy job atleast in unix prompt, so you need few lines of code to do these, awk script isn't big thing and still you can keep it and change the below line

Code:
 autorep -j $Job_Name  -w | grep -i $Job_Name |  awk '{ print $1 "\t\t\t\t   " $2 " " $3 " " $4 " " $5 " " $6 }'

to
Code:
 autorep -j $Job_Name  -w | grep -i $Job_Name |  awk '{ print $1 "\t\t\t\t   " $2 " " $3 " " $4 " " $5 " " $6 }'|awk -f time.awk

This should work out for you
# 5  
Do you want the time elapsed between start and end time of each job??

regards,
Ahamed
# 6  
Yes Ahamed
# 7  
did you try using time command, I'm not sure though what you mean by job here .
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