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How to list the content of a directory

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# 1  
Old 05-18-2011
How to list the content of a directory
Hi

I want to write a script that reads a directory name, checks if the directory exists and lists the content of that directory.

That's what I have at the moment.

Code:
function listDirectory 
{    
    echo "Give in a directory name"
    read name
    
    #Here I want to check if the directory exitst and then 
    #print the content of that directory (if exists off course)


    #If directory doesn't exists:
    echo "Directory doesn't exists. Closing the application..."
    exit 0   

}
listDirectory

# 2  
Old 05-18-2011
Code:
...
read name

if [ -d "$name" ]; then
  echo yep
  ls "$name"
else
  echo nope
  exit
fi

Read the man page for: test
# 3  
Old 05-18-2011
Hi,

Just some clue to help you find the answers :

Testing if it's a directory : [ -d $name ]
Print the content of a directory : ls $name

Good luck Smilie

Edit: damn i was too slow to answer Smilie
Last edited by Chirel; 05-18-2011 at 07:30 PM.. Reason: too slow
# 4  
Old 05-20-2011
Thanks guys!
# 5  
Old 05-20-2011
Quote:
Originally Posted by scottn
Code:
...
read name

if [ -d "$name" ]; then
  echo yep
  ls "$name"


There's no need for ls:
Code:
 printf "%s\n" "$name/"*

Quote:
Code:
else
  echo nope
  exit
fi

Read the man page for: test
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