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Grep regular expression to get part of a line

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# 1  
Old 05-07-2011
Data Grep regular expression to get part of a line
Hi I just started on GNU Grep with regex and am finding it very challenging and need to ask for help already...

here is the problem, I have a page (MYFILE) which consists of the following....
Code:
<div>
<input type="hidden" name="__EVENTTARGET" id="__EVENTTARGET" value="" />
<input type="hidden" name="__EVENTARGUMENT" id="__EVENTARGUMENT" value="" />
<input type="hidden" name="__VIEWSTATE" id="__VIEWSTATE" value="/wEPDwUKMTM3NjUMkY3RsMDM=" />
</div>

I want to Return the dynamic value on the __VIEWSTATE line.........
Code:
id="__VIEWSTATE" value="/wEPDwUKMTM3NjUMkY3RsMDM=" />

therefore expected result in this case would be......
Code:
/wEPDwUKMTM3NjUMkY3RsMDM=

I have been looking at
Code:
grep -o "(?<=__VIEWSTATE\" value=\")(?<val>.*?)(?=\")" myfile

Im not even sure if I need -o or not

However this returns nothing at all. Can you please help me to correct it ?

Many thanks in advance
Last edited by Scott; 05-07-2011 at 02:02 PM.. Reason: Please use code tags
# 2  
Old 05-07-2011
Code:
awk -F"\"" '/VIEWSTATE/{print $(NF-1)}' yourfile

Code:
sed '/VIEWSTATE/!d;s/"[[:blank:]]*[^"]*$//;s/.*"//' yourfile

This User Gave Thanks to ctsgnb For This Post:
noobie74645
# 3  
Old 05-08-2011
very quick and accurate response, checked on awk and worked perfectly, many many thanks!
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