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awk print variable

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# 1  
Old 05-07-2011
awk print variable
I have list of files:

Code:
ls
a.pdf
b.pdf
c.pdf

and so on...

and I have a file like this:

Code:
cat file1
apple
mango
pear

and so on...

I want to rename my file like this:

Code:
mv a.pdf a-apple.pdf
mv b.pdf b-mango.pdf
mv c.pdf c-pear.pdf

and so on...

So far I have in mind something like this:

Code:
for i in `ls`
do
mv $i $(echo $i|awk -F. '{print $1'$(awk {NR==$j} file1)'"."$2})'
done

but I know that has many problems which I need some help to solve.
Please help. Thanks.
Last edited by radoulov; 05-07-2011 at 04:00 AM.. Reason: Code tags!
# 2  
Old 05-07-2011
Try this

Code:
#!/bin/ksh

j=1
for i in *.pdf; do
prefix=$( echo $i | cut -f1 -d"." ); suffix=$( echo $i | cut -f2 -d"." )
newfile=$prefix"-"$( awk -F. -v j=$j 'NR==j {print $1}' file1 )"."$suffix
mv $i $newfile; ((j=j+1))
done

regards,
Ahamed
# 3  
Old 05-07-2011
Another one:

Code:
awk 'BEGIN {
  while ((getline < "file1") > 0) { 
    split(ARGV[ ++c ], x, ".")
    printf "mv -- \"%s\" \"%s-%s.%s\"\n", \
      ARGV[c], x[1], $1, x[2]
  }
}' *.pdf

An example:

Code:
zsh-4.3.11[t]% cat file1
apple
mango
pear
zsh-4.3.11[t]% ls *pdf
a.pdf  b.pdf  c.pdf
zsh-4.3.11[t]% awk 'BEGIN {
quote>   while ((getline < "file1") > 0) { 
quote>     split(ARGV[ ++c ], x, ".")
quote> printf "mv -- \"%s\" \"%s-%s.%s\"\n", \
quote>   ARGV[c], x[1], $1, x[2]
quote>   }
quote> }' *.pdf | bash -xv
mv -- "a.pdf" "a-apple.pdf"
+ mv -- a.pdf a-apple.pdf
mv -- "b.pdf" "b-mango.pdf"
+ mv -- b.pdf b-mango.pdf
mv -- "c.pdf" "c-pear.pdf"
+ mv -- c.pdf c-pear.pdf
zsh-4.3.11[t]% ls *pdf
a-apple.pdf  b-mango.pdf  c-pear.pdf

These 2 Users Gave Thanks to radoulov For This Post:
ahamed101 Peasant
# 4  
Old 05-07-2011
Thank you to both of you. I am going to test it it just that I just realized that my pdf files order is all wrong. The files order is like this when I run ls:
Code:
filex-1.pdf
filex-11.pdf
filex-2.pdf
filex-23.pdf
filex-216.pdf
filex-3.pdf
filex-35.pdf

and so on.....

How can I sort it so it will be like this:
Code:
filex-1.pdf
filex-2.pdf
filex-3.pdf
filex-11.pdf
filex-23.pdf
filex-35.pdf
filex-216.pdf

I think may be I can add "0" before the number part of the file names, so if the total of digit is only 1 add 2 more "0"s in front of it and add 1 more "0" if the total of digit is 2. Any better ideas on how shell script may help?
# 5  
Old 05-07-2011
It's easy to fix,
how exactly the new file names should look like?
# 6  
Old 05-07-2011
The code below will rename filex-1.pdf to filex-1-apple.pdf:


Code:
printf '%s\n' *.pdf |
  sort -t- -k2n |
    awk -F. 'getline f1 < "file1" {
      printf "mv -- \"%s\" \"%s-%s\.%s\"\n", \
        $0, $1, f1, $2
      }' | bash -xv

This User Gave Thanks to radoulov For This Post:
zorrox
# 7  
Old 05-07-2011
Your first codes seem to be very advance to a newbie like me. but thank you radoulov. it works. Can you explain your codes:
Code:
awk 'BEGIN {
  while ((getline < "file1") > 0) { 
    split(ARGV[ ++c ], x, ".")
    printf "mv -- \"%s\" \"%s-%s.%s\"\n", \
      ARGV[c], x[1], $1, x[2]
  }
}' *.pdf
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