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Getting the file extension

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# 1  
Old 04-26-2011
Getting the file extension
I have a file

Code:
n06-z30-sr65-rgdt0p25-varp0.25-8x6drw-test.cmod

and I want to get the extension.

At the moment I have

Code:
set filextension = `echo $f | awk 'BEGIN {FS="."} {print $2}'`

which of course does not work as there is a point in varp0.25
# 2  
Old 04-26-2011
what shell? modern bash:

Code:
var=n06-z30-sr65-rgdt0p25-varp0.25-8x6drw-test.cmod
echo ${var##*.}
cmod

# 3  
Old 04-26-2011
If your shell has variable substitution, and assuming the extension is supposed to be "cmod"

Then this ought to work:

Code:
 
my_file=n06-z30-sr65-rgdt0p25-varp0.25-8x6drw-test.cmod
my_ext=${my_file##*.}
echo $my_ext
cmod

# 4  
Old 04-26-2011
I am using csh

I need both the filename and the extension. At the moment it is as below

Code:
set filename = `echo $f | awk 'BEGIN {FS="."} {print $1}'`
set filextension = `echo $f | awk 'BEGIN {FS="."} {print $2}'`

# 5  
Old 04-26-2011
Code:
#!/bin/csh
set pathvar=/home/WSJ091305.txt
echo $pathvar:r
echo $pathvar:h
echo $pathvar:t
echo $pathvar:e

Code:
#
# The result of executing this script is:
#
/home/WSJ091305
/home
WSJ091305.txt
txt

# 6  
Old 04-26-2011
You want the last field, which in awk is referenced by $NF.

Regards,
Alister
# 7  
Old 04-26-2011
I have done the below to get the file extension.

Code:
  set filextension = `echo $f | awk 'BEGIN {FS="."} {print $NF}'`

But what should I do to get the file name?
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