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Automatic variable assignment inside a for loop

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# 1  
Old 04-26-2011
Question Automatic variable assignment inside a for loop
Code:
cs1=`echo "scale=8;($css1/$css0)*100"|bc`
cs2=`echo "scale=8;($css2/$css0)*100"|bc`
cs3=`echo "scale=8;($css3/$css0)*100"|bc`
cs4=`echo "scale=8;($css4/$css0)*100"|bc`
cs5=`echo "scale=8;($css5/$css0)*100"|bc`
cs6=`echo "scale=8;($css6/$css0)*100"|bc`
cs7=`echo "scale=8;($css7/$css0)*100"|bc`
cs8=`echo "scale=8;($css8/$css0)*100"|bc`
cs9=`echo "scale=8;($css9/$css0)*100"|bc`

Instead of using the above code, if I use the below to reduce the script size, it is not working. Please help

Code:
for i in 1 2 3 4 5 6 7 8 9
do
eval cs$i=`echo "scale=8;($css'$i'/$css0)*100"|bc`
done

# 2  
Old 04-26-2011
in your for loop try to replace with the line (there are 6 simple quote,2 back quote and 2 double quote... don't forget some...)

Code:
eval 'cs'$i'=`echo "scale=8;($css'$i'/$css0)*100"|bc`'

Otherwise
Code:
for i in 1 2 3 4 5 6 7 8 9
do
t=$(eval echo "\(\$css$i/\$css0\)*100")
eval cs$i=`echo "scale=8;$t"|bc`
done

Last edited by ctsgnb; 04-28-2011 at 11:50 AM..
# 3  
Old 04-26-2011
Since you can't eval in eval:
Code:
for i in {1..8}
do
    tmp="cs$i=\$(echo \"scale=8;(\$css$i/$css0)*100\"|bc)"
    eval $tmp
    tmp2="echo cs$i is \$cs$i"
    eval $tmp2
done

# 4  
Old 04-26-2011
I tested & fixed my previous post, use simple quoting for the one line eval :

Give a try to the following :

Code:
for i in 1 2 3 4 5 6 7 8 9
do
eval 'cs'$i'=`echo "scale=8;($css'$i'/$css0)*100"|bc`'
done

(don't forget any of the 6 simple quote)
Last edited by ctsgnb; 04-28-2011 at 11:52 AM..
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