Shell Programming and Scripting

for i in 3 4 5 6
do
        cs$i=`awk -F"|" 'BEGIN{sum=0}{sum=sum+$'$i'}END{printf("%d\n", sum)}' css`
done
echo $cs3 $cs4 $cs5 $cs6

awk -F"|" 'BEGIN{sum=0}{sum=sum+$3}END{printf("%d\n", sum)}' css
awk -F"|" 'BEGIN{sum=0}{sum=sum+$4}END{printf("%d\n", sum)}' css
awk -F"|" 'BEGIN{sum=0}{sum=sum+$5}END{printf("%d\n", sum)}' css
awk -F"|" 'BEGIN{sum=0}{sum=sum+$6}END{printf("%d\n", sum)}' css
awk -F"|" 'BEGIN{sum=0}{sum=sum+$7}END{printf("%d\n", sum)}' css
awk -F"|" 'BEGIN{sum=0}{sum=sum+$8}END{printf("%d\n", sum)}' css
awk -F"|" 'BEGIN{sum=0}{sum=sum+$9}END{printf("%d\n", sum)}' css

#!/bin/ksh

IFS="|"
# Read individual lines from inputfile
while read LINE
do
        # Split $LINE apart on IFS into the array CSI
        set -A CSI $LINE

        # Start at column 1.  Column 0 would be that time column
        N=1
        while [ ! -z "${CSI[$N]}" ]
        do
                # If the column is blank, set it to zero
                [ -z "${CS[$N]}" ] && ((CS[$N]=0))
                # Add the number to the column
                ((CS[$N] += CSI[$N]))
                # Add one to N
                ((N++))
        done
done < inputfile

N=1
while [ ! -z "${CS[$N]}" ]
do
        echo "cs$N=${CS[$N]}"
        ((N++))
done

$ cat >inputfile <<EOF
1|2|3|4
5|6|7|8
9|10|11|12
EOF
$ ./addcol.sh
cs1=18
cs2=21
cs3=24
$

#!/bin/ksh

IFS="|"
# Read individual lines from inputfile
while read TIME LINE
do
        # Split $LINE apart on IFS into the array CSI
        set -A CSI $LINE

        N=0
        while [ ! -z "${CSI[$N]}" ]
        do
                [ -z "${CS[$N]}" ] && ((CS[$N]=0))
                ((CS[$N] += CSI[$N]))
                ((N++))
        done
done < inputfile

N=0
while [ ! -z "${CS[$N]}" ]
do
        echo "cs$N=${CS[$N]}"
        ((N++))
done

LINE="`awk -v FS='|' '{ for(N=2; N<=NF; N++) { T[N]+=$N; MAX=N; } }
END { for(N=2; N<=MAX; N++) printf("%s ", T[N]); printf("\n"); }' inputfile`"

set -A CS $LINE

N=0
while [ ! -z "${CS[$N]}" ]
do
        echo "CS$N=${CS[$N]}"
        ((N++))
done