Problem with a BDF script...


 
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# 1  
Old 04-14-2011
Problem with a BDF script...

Hi,

I'm trying to use an old script I found of the internet a while back, I forget where its from. Its supposed to convert the bdf function and display filesystem size in MB's and line it up however it never worked...

Here is the error:

Quote:
./bdf.sh
Filesystem Mbytes used avail %used Mounted on
syntax error The source line is 2.
The error context is
{ printf("%s %10d %10d %10d %4s %s\n",$1,$2/1 >>>
<<<
awk: The statement cannot be correctly parsed.
The source line is 2.
And here is the code:

Code:
#!/usr/bin/sh

echo "Filesystem          Mbytes       used      avail %used Mounted on"

bdf $1 | grep -v Filesystem | awk '{ printf("%s %10d %10d %10d %4s  %s\n",$1,$2/1
024,$3/1024,$4/1024,$5,$6)}'

Can someone help me make sense of this?

Thanks
# 2  
Old 04-14-2011
The script is one line only.

If you copy and paste it, the result will be two lines.

Try this:
Code:
bdf $1 | grep -v Filesystem | awk '{ printf("%s %10d %10d %10d %4s  %s\n",$1,$2/1024,$3/1024,$4/1024,$5,$6)}'

This User Gave Thanks to Shell_Life For This Post:
# 3  
Old 04-14-2011
Heh, thanks. I am a newb...
# 4  
Old 04-14-2011
Quote:
Originally Posted by Shell_Life
The script is one line only.

If you copy and paste it, the result will be two lines.

Try this:
Code:
bdf $1 | grep -v Filesystem | awk '{ printf("%s %10d %10d %10d %4s  %s\n",$1,$2/1024,$3/1024,$4/1024,$5,$6)}'

Useless use of grep:
Code:
bdf $1 | awk '!/Filesystem/{ printf("%s %10d %10d %10d %4s  %s\n",$1,$2/1024,$3/1024,$4/1024,$5,$6)}'

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