Shell Programming and Scripting

Good Morning/Afternoon All,

I am having some trouble creating a variable called "total" to display the sum of the values in a specific field, $6 for example.

The data I am working on is in the following form:

Code:

John Doe:(555) 555-5555:1:2:3
Jane Doe:(544) 444-5556:4:5:6
Moe Doe:(654) 333-9999:7:8:9

I am using ":" as the field separator in order to have a total of 5 fields.
I then add the values in fields 3,4,5 to generate field 6

Code:

John Doe:(555) 555-5555:1:2:3:6
Jane Doe:(544) 444-5556:4:5:6:15
Moe Doe:(654) 333-9999:7:8:9:24

Now I want to add all the values in field 6 to generate a single total for the entire file, this is where I am stuck.

I currently have the following for my nawk script

Code:

nawk -F: '{split($0,six,":"); total=(six[3]+six[4]+six[5]); print total, NF}' filename

To my understanding, the above code creates an array "six" which stores all the values for each record(line) while using ":" as the separator.

I am thinking of storing the values in field 6 to a separate array called "dtotal" then doing a sum for all values in dtotal to give me the overall total for the file because I also need to display an average and highest value for field 6.

Any and all help is greatly appreciated.
Thanks in Advance.

Something like this?

Code:

awk -F: '{$6=$3+$4+$5;total+=$6}END{print "Total = " total}1' OFS=":" file

Thank you very much.
I spent the last couple of hours trying to do this with a for loop
Many many thanks once again.