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SED - delete words between two possible words

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# 1  
Old 04-11-2011
SED - delete words between two possible words
Hi all,

I want to make an script using sed that removes everything between 'begin' (including the line that has it) and 'end1' or 'end2', not removing this line.

Let me paste an 2 examples:

Code:
anything before
any string begin
few lines of content
end1
anything after

Code:
anything before
any string begin
few lines of content
end2
anything after

The desired output are:

Code:
anything before
end1
anything after

and
Code:
anything before
end2
anything after

I was trying something like sed '/begin/,/end1|end2/ d' <input >output but its very far away from what I want.


Thank you very much for helping
# 2  
Old 04-11-2011
Code:
sed  '/begin/,/end[12]/{/end[12]/!d;}' infile

This User Gave Thanks to radoulov For This Post:
meuser
# 3  
Old 04-11-2011
Thank you, radoulov.

Let me ask one more question, because I can't find on Google neither regex tutorials: if it was foo/bar instead of end1/end2 ?
# 4  
Old 04-12-2011
In that case you should use alternation (|) as in your original command:

Code:
sed  '/begin/,/foo\|bar/{/foo\|bar/!d;}' infile

It should be noted that only few sed implementations support alternation.
This User Gave Thanks to radoulov For This Post:
meuser
# 5  
Old 04-12-2011
That worked ! thank you my friend!
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