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Find directories by regex

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# 1  
Old 04-11-2011
Find directories by regex
Hello,
I want to check if directories exist with a regex expression

dir1=/temp/local/*/home (exists on file system)

dir2=/temp/server/*/logs (does not exist on file system)

I want to check if there are any directories with the above regex

Code:
Code:
if [[ -d ${dir} ]];then
   echo "Directory exist"
else 
   echo "Directory does not exist"
fi

For both dir1 and dir2 "Directory does not exist" is printed.

Any way to make this check.

Thanks
# 2  
Old 04-11-2011
if [ `find ${dir} -type d -prune` ]; then
echo "Directory exist"
else
echo "Directory does not exist"
fi
Last edited by pbillast; 04-11-2011 at 12:11 PM..
# 3  
Old 04-11-2011
Using only basic sh and printing a line for each match found:
Code:
for d in /temp/local/*/home/ /temp/server/*/logs/; do
        if [ -d "$d" ]; then
                echo "$d: exists"
        else
                echo "$d: no match"
        fi
done

Regards,
Alister
This User Gave Thanks to alister For This Post:
gogineni
# 4  
Old 04-11-2011
Or just
Code:
ls -d /temp/local/*/home /temp/server/*/logs

... but ok i know what you guys are going to say :
.... argument list too long & MAX_ARGS constraints ... Smilie

Stick with alister's suggestion, that's the best one (... the suggestion Smilie )
# 5  
Old 04-11-2011
Quote:
Originally Posted by ctsgnb
Stick with alister's suggestion, that's the best one (... the suggestion Smilie )
Sticking too many args in a for statement doesn't make too many args not be too many args. Neither does sticking 'find' in backticks make too many args not be too many args.

Just searching for directory names though, I don't think is likely to cause too many arguments.
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