passing arguments to external script


 
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# 1  
Old 04-04-2011
passing arguments to external script

Hi!

I have a python script that requires arguments and these arguments are file paths. This script works fine when executed like this:
/my_python_script "file_path1" "file_path2"
(i added quotes as some file names may have weird characters)

the issue happens when i launch my python script from within a bash script. i do get the variable file_paths as "file_path1" "file_path2"

in my bash script i have:
echo "$file_paths"
and this will return:
"file_path1" "file_path2"

but when my bash script contains:
/my_python_script "$file_paths"
it produces an incorrect result

Can anyone please shed some light into what i'm missing
# 2  
Old 04-04-2011
Quote:
Originally Posted by gigagigosu
in my bash script i have:
echo "$file_paths"
and this will return:
"file_path1" "file_path2"
I sincerely doubt that. echo doesn't put quotes around things like that.

What's the actual contents of the file_paths variable?
Quote:
but when my bash script contains:
/my_python_script "$file_paths"
it produces an incorrect result
Incorrect in what fashion?
# 3  
Old 04-04-2011
my script is:

Code:
source_folder=/my_files
cd "$source_folder"
if [ "$(ls -A)" ]; then
for PDF_file in *
 do
  quoted_filename=\"$source_folder/$PDF_file\"
  all_PDFs="$all_PDFs $quoted_filename"
 done
fi

echo "$all_PDFs"
/Scripts/Combine_PDFs_python.py -o /TEST`date +%H-%M-%S`.pdf "$all_PDFs"

this will output:
Code:
 "/my_files/1.pdf" "/my_files/2.pdf"


my python script (part of the OS) is supposed to join these PDFs but it produces an empty PDF

Last edited by Franklin52; 04-04-2011 at 02:11 PM.. Reason: Please use CODE TAGS
# 4  
Old 04-04-2011
Quote:
Originally Posted by gigagigosu
Hi!

I have a python script that requires arguments and these arguments are file paths. This script works fine when executed like this:
/my_python_script "file_path1" "file_path2"
(i added quotes as some file names may have weird characters)

the issue happens when i launch my python script from within a bash script. i do get the variable file_paths as "file_path1" "file_path2"

in my bash script i have:
echo "$file_paths"
and this will return:
"file_path1" "file_path2"

but when my bash script contains:
/my_python_script "$file_paths"
it produces an incorrect result

Can anyone please shed some light into what i'm missing
Don't use quotes:
Code:
/my_python_script $file_paths

# 5  
Old 04-04-2011
Franklin52,

i tried that with same undesired result
# 6  
Old 04-04-2011
What happens when you run the script manually with those names?

There may be other reasons than filenames that your script is failing.

Also, what are the exact contents of the file_paths variable? Not made up, not paraphrased.

Last edited by Corona688; 04-04-2011 at 12:37 PM..
# 7  
Old 04-04-2011
my bash script currently end like this:
Code:
/Scripts/Combine_PDFs_python.py -o /TEST`date +%H-%M-%S`.pdf "$all_PDFs"

and it this will output:
Code:
"/my_files/1.pdf" "/my_files/2.pdf"

if i add two lines as per below:
Code:
sleep 1 # to create a different output file
/Scripts/Combine_PDFs_python.py -o /TEST`date +%H-%M-%S`.pdf "/my_files/1.pdf" "/my_files/2.pdf"

will produce the expected result

---------- Post updated at 12:36 PM ---------- Previous update was at 11:38 AM ----------
Code:
echo $all_PDFs
"/my_files/1.pdf" "/my_files/2.pdf"

/Scripts/Combine_PDFs_python.py -o /TEST`date +%H-%M-%S`.pdf $all_PDFs

this command produces an empty PDF (incorrect)
Code:
/Scripts/Combine_PDFs_python.py -o /TEST`date +%H-%M-%S`.pdf "/my_files/1.pdf" "/my_files/2.pdf"

this command produces a correct result, the only difference is replacement of $all_PDFs with content... what am i doing wrong?

Last edited by Franklin52; 04-04-2011 at 02:14 PM.. Reason: Please use code tags
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