awk to remove leading zeros for a hex number


 
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# 1  
Old 04-01-2011
awk to remove leading zeros for a hex number

Is it possible by using awk to remove leading zeros for a hex number?

ex:
0000000011179E0A -> 11179E0A

Thank you!
# 2  
Old 04-01-2011
Code:
$ echo 0000000011179E0A | awk '{print gensub(/^0*/,"","")}'
11179E0A

This User Gave Thanks to mirni For This Post:
# 3  
Old 04-01-2011
Code:
$ echo 0000000011179E0A | ruby -e 'print gets.sub(/^0*/,"")'
11179E0A

This User Gave Thanks to kurumi For This Post:
# 4  
Old 04-01-2011
Convert to base 10 using bash/ksh base conversion and back to hex with printf:

Code:
$ printf "%X" $((16#0000000011179E0A))
11179E0A

Edit: Beware - After more testing of the above I found it dosn't work real well with big hex numbers (particularly if first hex digit is > 8), probably best to use string functions to remove the zeros:

Code:
 $ echo 0000000011179E0A | sed 's/^0*//'
11179E0A


Last edited by Chubler_XL; 04-01-2011 at 01:39 AM..
This User Gave Thanks to Chubler_XL For This Post:
# 5  
Old 04-01-2011
Code:
echo "0000000011179E0A" | sed 's/^0*//'

This User Gave Thanks to tene For This Post:
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