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last task for my script


 
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# 1  
Old 03-23-2011
MySQL last task for my script

hi,

infile-
Code:
create table salary
( occupation_code char(40),
  earnings decimal(10,2),
  occ_yearend integer
);

outfile-
Code:
salary:create table salary
salary:( occupation_code char(40),
salary:  earnings decimal(10,2),
salary:  occ_yearend integer
salary:);

Thanks.

Last edited by Scott; 03-23-2011 at 02:06 PM.. Reason: Please use code tags, not quote tags, for code
# 2  
Old 03-23-2011
Try:
Code:
awk 'NR==1{x=$3}{$0=x":"$0}1' file

# 3  
Old 03-23-2011
Bug

Quote:
Originally Posted by bartus11
Try:
Code:
awk 'NR==1{x=$3}{$0=x":"$0}1' file

The problem is my in file has many DDL scripts like below

Code:
create table contract_occ
( occupation_code char(40),
  con_ref int,
  cntrctid_number char(20));
create table salary
( occupation_code char(40),
  earnings decimal(10,2),
  occ_yearend integer);
...


Code:
contract_occ:create table contract_occ
contract_occ:( occupation_code char(40),
contract_occ:  con_ref int,
contract_occ:  cntrctid_number char(20));
salary:create table salary
salary:( occupation_code char(40),
salary:  earnings decimal(10,2),
salary:  occ_yearend integer);
...

So the append string varies acorss the script, the key here is to identify the table name with "create table" command and apply it to all the following lines till the next similar command exists.

Thanks.
# 4  
Old 03-23-2011
Code:
awk '/create table/{x=$3}{$0=x":"$0}1' file

This User Gave Thanks to bartus11 For This Post:
# 5  
Old 03-23-2011
Quote:
Originally Posted by bartus11
Code:
awk '/create table/{x=$3}{$0=x":"$0}1' file


Thanks. This works perfect.

I just tried this with my own lengthy script, that works fine too.

Code:
while read line
do
    if [ `echo $line | grep "create table " | wc -l` -gt 0 ]
    then
        tablename=`echo $line | awk '{print $3}'`
    fi
        echo "$tablename:" $line >> outfile
done < infile

Anyway, Thanks once again!

Moderator's Comments:
Mod Comment Please use code tags when posting code

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