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converting Date format

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# 1  
Old 03-18-2011
converting Date format
Dear Friends,
We have date in output as MM/DD/YYYY format and I want to convert it in DD/MM/YYYY format.

e.g.
12/31/2010 to 31/12/2010

We have checked forum for the solution but we are not getting matching query.
Please guide us

Thanks
Anushree.
# 2  
Old 03-18-2011
Code:
kent$ echo "12/31/2010" | awk -F'/' '{print $2 FS $1 FS $3}'
31/12/2010

kent$ echo "12/31/2010" | sed -r 's#([0-9]{2})/([0-9]{2})#\2/\1#' 
31/12/2010

# 3  
Old 03-18-2011
It worked.
Thanks for a clean and easy to understand solution
Thanks a lot.
# 4  
Old 03-18-2011
If you have the control on the script that generates this output, you should change directly the way the output is generated ( date '+%d/%m/%Y' ) instead of performing an additionnal conversion step.

(format it the right way directly instead of formatting it the wrong way + converting it to a right format)
# 5  
Old 03-18-2011
GNU date
Code:
date -d"12/31/2010" '+%d/%m/%Y'

# 6  
Old 03-18-2011
Dear Pravin,
We are now able to generate out put as desired. But we want output with "-" separator.
i.e.
31/12/2010

to

31-12-2010

Can we do it?
Thanks
Anu.
# 7  
Old 03-18-2011
Code:
date -d"12/31/2010" '+%d-%m-%Y'

OR
Code:
echo "12/31/2010" | awk -F'/' '{print $2 OFS $1 OFS $3}' OFS="-"

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