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How to print last word of line

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# 1  
Old 03-10-2011
How to print last word of line
Hi,

How to print last word of line?

Code:
#!/bin/bash

x1="This is Kiran"
echo "$x1"

how to print "Kiran" in new variable.i.e x2=kiran
# 2  
Old 03-10-2011
Code:
x1="This is Kiran"
x2=`echo ${x1##* }`
echo $x2
Kiran

This User Gave Thanks to yinyuemi For This Post:
kiran_j
# 3  
Old 03-10-2011
Another way..
Code:
x1="This is Kiran"
x2=`echo $x1|cut -d ' ' -f3`

This User Gave Thanks to michaelrozar17 For This Post:
kiran_j
# 4  
Old 03-10-2011
There is always another way in Linux :Smilie

x1="This is Kiran"
x2= `echo $x1 | awk '{ print $NF }'
This User Gave Thanks to r05h777 For This Post:
kiran_j
# 5  
Old 03-10-2011
Quote:
Originally Posted by yinyuemi
Code:
x1="This is Kiran"
x2=`echo ${x1##* }`
echo $x2
Kiran

I guess no need of "echo" here.

Code:
x2=${x1##* }

Another way,

Code:
expr "$x1" : '.* \(.*\)'

These 2 Users Gave Thanks to clx For This Post:
kiran_j yinyuemi
# 6  
Old 03-10-2011
Hi,

I have written one script :

Code:
#!/bin/bash

echo -n -e "\nEnter file name : "
read File
Temp=`find /apps12i -name $File`
echo "$Temp"

Output:

Enter file name : abc.log

/path1/abc.log
/path2/abc.log

I need script that should print "abc.log file present in multiple path"
so how do i compare "abc.log " ????
# 7  
Old 03-10-2011
You should start new thread for different topic/issue.

Try something like...

Code:
Temp=`find /apps12i -name $File | wc -l`

if [ "$Temp" -gt 1 ]; then
 echo "abc.log file present in multiple path"
fi

This User Gave Thanks to clx For This Post:
kiran_j
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