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grep with cut option??


 
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# 1  
Old 03-09-2011
grep with cut option??

This is my command-line code in my script,

Code:
passwd=`grep $passwd $userfile |  cut -f2 -d: login_users > retrieve`

the
Code:
cut -f2 -d: login_users > retrieve

searches and prints the whole column two. what I need is one of the items in the column two only.. what option can I add to my cut command??

here is an example, all files in column 2..

aaa
bbb
ccc

then, what I want to print is just the aaa.. what will I do??
# 2  
Old 03-09-2011
Try this :

Code:
passwd=`grep $passwd $userfile | awk -F ":" '{print $2}' | awk NR==3`

This will select the 2nd field and the 3rd line.

Last edited by fhernu; 03-09-2011 at 07:47 AM.. Reason: Spelling fault
# 3  
Old 03-09-2011
Code:
login_user="aaa"
passwd=`awk -v p=$login_user -F: '$0~p {print $2}' $userfile`


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