Shell Programming and Scripting

Hi friends,
I have a file list1 which has these 2 columns like

Code:

616449 0
434453 1
2151083 0
2226536 0
2132382 0
2136814 0

I have to put the result of col1 -col2 into another file list2 linewise.

e.g. It gives the below result if use the below code:

Code:

awk '{ print $1 - $2 }' list1 > list2

616449
434453
2.15108e+06 
2.22654e+06 
2.13238e+06 
2.13681e+06

I don't want the exponential values
The problem with my code is that it turns the subtraction result into exponential for values greater than 6 digits. How should i modify the awk command (using some formatting features...i tried it but no success) to get the result in the format like given below

Code:

616449
434453
2151083
2226536 
2132382
2136814

Also if i try to convert the above exponential values to integer i use some values like 2.15108e+06 becomes 2151080 instead of required 2151083.


For now i have used the below workaround ,
But can anyone please tell me how to modify my above awk syntax to achieve it.

Code:

while read line
 do
 var1=`echo $line | awk '{ print $1}'`
 var2=`echo $line | awk '{ print $2}'`
 y=`expr $var1 - $var2`
 echo $y >> list2
done < list1

I have searched this forum number of times for this ,but no success still.


Regds,
Kunwar

Code:

awk '{ printf "%.0f\n", $1 - $2 }' list1

awesome man!!thank you so much..it works perfect.