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Array declaration in Shell script

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# 1  
Old 02-28-2011
Data Array declaration in Shell script
this is my code

Code:
        declare -a USERCERT
        declare -a CACERT
        declare -a KEYSRC

this is the error

Code:
+ declare -a USERCERT
./clone.sh: 1: declare: not found
+ declare -a CACERT
./clone.sh: 1: declare: not found
+ declare -a KEYSRC
./clone.sh: 1: declare: not found


Suggest resolution....
# 2  
Old 02-28-2011
Code:
# ksh
typeset -A array 
# bash
declare -a array

# 3  
Old 02-28-2011
Quote:
Originally Posted by xerox
Code:
+ declare -a KEYSRC
./clone.sh: 1: declare: not found


declare is a bashism not found in other shells. In ksh, use typeset.

And most shells do not have arrays at all.
# 4  
Old 02-28-2011
i need it in shell script....

Is it not possible to define my own array name?
# 5  
Old 02-28-2011
What is your shell ? ksh, bash, ...
And most of use case, you don't need to define array. Use it.
Code:
a[1]=value
a=( * )
set -A array  -- $*

This User Gave Thanks to kshji For This Post:
xerox
# 6  
Old 02-28-2011
bash...

so the array size doesnt't matter?

Code:
set -A array  -- $*

what does this line do?
# 7  
Old 02-28-2011
Quote:
Originally Posted by xerox
i need it in shell script....

Is it not possible to define my own array name?

Yes ... if you are using a shell which supports arrays.

First, don't declare the arrays; just assign values to them.

---------- Post updated at 01:21 AM ---------- Previous update was at 01:13 AM ----------

Quote:
Originally Posted by xerox
bash...

If you were running the script in bash, you wouldn't have seen those error messages.
Quote:

so the array size doesnt't matter?

No (so long as there is enough memory).
Quote:

Code:
set -A array  -- $*

what does this line do?

In bash, there is no -A option to set.

In ksh, it assigns all the words (not the arguments) on the command line as elements in the array named array.

The bash equivalent (which also works in ksh93) is:
Code:
array=( $* )

Though what was probably meant was:
Code:
set -A array  -- "$@"

Which should be written:
Code:
array=( "$@" )

Last edited by cfajohnson; 02-28-2011 at 02:29 AM..
This User Gave Thanks to cfajohnson For This Post:
xerox
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