Get Formatted Date from Unix Epoch

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# 1  
Get Formatted Date from Unix Epoch

Could someone please explain how to get a formatted date from the unix epoch (the number of seconds since Jan 1, 1970)

For example.,
If the input is 1297969816, then the output should be 2011-02-17 in YYYY-MM-DD formatted manner.

I am using AIX sh shell. Tried date -d and date --date, these didnt work . Cant use perl, python etc, only sh,ksh shells.

Thanks in anticipation.
# 2  
datecalc is a ksh script that I posted to the site. Using datecalc most date arithmetic problems become easy.
$ cat unixdate
#! /usr/bin/ksh
((uday=epoch/86400))   # 86400 seconds in a day
((uday=uday+40587))    # 40587 is the modified julian day number of Jan 1, 1970
./datecalc -j $uday
$ ./unixdate
2011 2 17

This User Gave Thanks to Perderabo For This Post:
# 3  
C program

Here is a C program I got back in 2004. You should be able to compile it on any UNIX system with the standard C compiler. You run it and provide your number of seconds since EPOCH value and it will print out the date and time. You could modify the print statement or use some other shell mechanism to change the output to what you are looking for.
 * File:        convtime.c
 * Description: Convert OpCdatetime (seconds since EPOCH) to calendar datetime.
 *              Calendar datetime is written to stdout.
 * Use:        convtime <OpCdatetime>
 * Revision History
 * ================
 * Name        Date    Description
 * J. Peereboom 960722    Creation

 * System includes
#include <stdio.h>
#include <stdlib.h>
#include <strings.h>
#include <time.h>

 * Function:    main()
 * Description: Main entry point.
 * Called by:   None
 * In:          argc: Argument count.
 *              argv: The arguments. argv[1] is the datetime to be converted.
 * Out:         None
 * InOut:       None
 * Return:      0.
 *              Prints the calendar datetime on stdout.

extern int main(argc, argv)
 int   argc;
 char *argv[];
    struct tm *t;
    time_t seconds;

    if (argc != 2)
    fprintf(stderr,"usage: doit time\n");

    sscanf (argv[1], "%ld", &seconds);
    t = localtime(&seconds);
    printf("%4d%02d%02d %02d:%02d:%02d\n"
            , t->tm_year+1900
            , t->tm_mon+1
            , t->tm_mday
                        , t->tm_hour
            , t->tm_min
            , t->tm_sec
    return 0;

Moderator's Comments:
Mod Comment
Please use code tags when posting data and code samples!

Last edited by vgersh99; 02-17-2011 at 01:56 PM.. Reason: code tags, please!
This User Gave Thanks to DaveJohnson For This Post:
# 4  
On modern versions of AIX the /usr/bin/ksh93 shell is also available. If this is the case, then the following will work:
$ printf "%(%Y-%m-%d)T\n" #1297969816

This User Gave Thanks to fpmurphy For This Post:
# 5  
Guys, Thank you All for your replies.
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