Shell Programming and Scripting

Greetings.

I have files that contains eleven fields in the file name. Each file has a specific meaning. My job is to list each file name and load the info into a database table for reporting.

My awk code does this (files have VER suffix):

Code:

    find . -name "*.VER" -exec ls '{}' ';' -printf %f\\t | awk -F"~" '{print $1"\t"$2"\t"$3"\t"$4"\t"$5"\t"$6"\t"$7"\t"$8"\t"$9"\t"$10"\t"$0}' > somefile.tab

It works fine except that it does something weird with the file name ($0): it repeats it like so (the 2 last fields from the right):

Code:

    RRR1	PRE	DTV_PREP	PREP05	JGM15453.	26	P	H23-600	029416589165	20110216	RRR1~PRE~DTV_PREP~PREP05~JGM15453.~26~P~H23-600~029416589165~20110216~090353.VER	./RRR1~PRE~DTV_PREP~PREP05~JGMDTV269~33~P~H21-200~029384120357~20110216~091829.VER

What am missing here? Any ideas?

Thanks for your input.

---------- Post updated at 12:25 PM ---------- Previous update was at 12:11 PM ----------

I removed " -printf %f\\t " and replaced $0 with $filename. It works now but display "./" right before the filename. How can remove these two leading characters?

Try removing -exec clause while leaving -printf.

Remove -exec and tweaked the printf() statement to add a newline character like so:

Code:

find . -name "*.VER" -printf %f\\n | awk -F"~" '{print $1"\t"$2"\t"$3"\t"$4"\t"$5"\t"$6"\t"$7"\t"$8"\t"$9"\t"$10"\t"$0}'

It worked like a charm. Thank you.