unary operator expected


 
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# 1  
Old 02-16-2011
unary operator expected

Code:
i=0
while [ $i -le $buf ]

Shell script reports an error "unary operator expected" pointing the above line.
$i by default is 0 and holds integer value and $buf is also holding integer value.

Please can some one let me know what is missing.

Thanks.
# 2  
Old 02-16-2011
Please post few more lines of the code and also let us know the shell and the OS you are working with..
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