awk help


 
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# 8  
Old 02-03-2011
thanks for the reply

however, i am sorry to say it does not solve my original problem

cat xxx.log

Code:
-rw-r--r--    1 xxxx sftponly        6 Feb  2 14:51 this_is_a_test_file1.txt
-rw-r--r--    1 xxxx sftponly        6 Feb  2 14:51 this is  a test      file2.txt
drwxr-xr-x    2 xxxx sftponly      512 Feb  2 15:04 test
-rw-r--r--    1 xxxx sftponly       13 Feb  3 09:53 this_is_a_new_test1.txt
-rw-r--r--    1 xxxx sftponly       13 Feb  3 09:53 thisisanewtest1.txt
sftp>

run this
Code:
cat xxx.log | sed "1,/^sftp> ls -ltr/d" | /usr/xpg4/bin/awk '{for(i=1;i<=8;i++){$i=""};}1'

get this
Code:
        this_is_a_test_file1.txt
        this is a test file2.txt
        test
        this_is_a_new_test1.txt
        thisisanewtest1.txt

i was expected e.g

Code:
this_is__a_test______file2.txt

have i implemented the solution incorrectly?
# 9  
Old 02-03-2011
Try:
Code:
/usr/xpg4/bin/sed 's/\([^ ]* *\)\{8\}//;s/$/~/' infile


Last edited by Scrutinizer; 02-03-2011 at 10:16 AM..
This User Gave Thanks to Scrutinizer For This Post:
# 10  
Old 02-03-2011
Quote:
Originally Posted by caciing_help
many thanks for your help.


I have tried this:
Code:
cat xxx.log | awk '{sub(".*" $8 FS,x)}{print $0 "~"}'
awk: syntax error near line 1
awk: illegal statement near line 1

but get the error? have id done something wrong
Have you tried this?
Code:
/usr/xpg4/bin/awk '{sub(".*" $8 FS,x)}{print $0 "~"}' file

This User Gave Thanks to Franklin52 For This Post:
# 11  
Old 02-03-2011
you should Franklin's solution.
Code:
nawk  '{sub(".*"$8 FS,"");gsub(" ","_")}1' file

This User Gave Thanks to ghostdog74 For This Post:
# 12  
Old 02-03-2011
Hi,

Another solution using 'gawk':
Code:
$ awk --version | head -1
GNU Awk 3.1.8
$ awk --posix 'BEGIN { FS="([[:graph:]]+[[:blank:]]+){8}" } { printf "%s\n", $2 }' infile
this is a test.txt 
this  test2   .txt
this is test 2.txt

Regards,
Birei
This User Gave Thanks to birei For This Post:
# 13  
Old 02-03-2011
hi guys got it working i think.


Code:
 
|/usr/xpg4/bin/awk '{sub(".*" $8 FS,x)}{print $0 }'

That seemed to do the trick.

Thanks for all the help
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