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# 8  
Old 02-02-2011
I changed it to this to try and get the months to sort:
Code:
awk -v FS=OFS="/" '!a[$2$1]++' filename

, but I don't think I'm getting the usage of
Code:
a[$1$2]

right for splitting the columns
# 9  
Old 02-02-2011
Hi, dba_frog.
Quote:
Originally Posted by dba_frog
i tried this
Code:
awk '!a[$1$2]++' filename

on this
Code:
01/Feb/2011   -- User Count : 27
  31/Jan/2011   --  User Count : 21
  02/Feb/2011   -- User Count : 24
  30/Jan/2011   --  User Count : 4

and it didn't sort by mo & day. But, I assumed that is because I didn't specify the correct columns.
The main purpose of this thread is to choose the correct line among lines that have the same value for a field.

Although sorting may be involved in some solutions, the purpose of most of the awk codes is to remove duplicates.

If you are interested in sorting your data, I suggest that you start a new thread.

Best wishes ... cheers, drl
# 10  
Old 02-02-2011
Have a look at stable sort. For example in GNU sort this is the -s option:
Code:
$ sort -us -k1,1n infile
1234 8888 bbb
2745 8888 bbb
3977 8888 aaa
4838 8888 aaa
9489 8888 bbb

# 11  
Old 02-02-2011
Thanks everyone...
Thanks, drl... that worked perfectly.

PA
# 12  
Old 02-03-2011
Hi, palex.
Quote:
Originally Posted by palex
Thanks everyone...
Thanks, drl... that worked perfectly.
PA
You are welcome.

It's possible that with the small sample we have, we were just lucky. You may need -- as Scrutinizer wrote -- to use the "-s" option in addition to "-u" on the sort ( not on the uniq ):
Code:
Finally, as a last resort when all keys compare
equal, `sort' compares entire lines as if no ordering options other
than `--reverse' (`-r') were specified.  The `--stable' (`-s') option
disables this "last-resort comparison" so that lines in which all
fields compare equal are left in their original relative order. 

-- excerpt from info coreutils sort

Good luck ... cheers, drl
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