fetch last line no form file which is match with specific pattern by grep command


 
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# 1  
Old 02-01-2011
fetch last line no form file which is match with specific pattern by grep command

Hi

i have a file which have a pattern like this
Code:
Nov 10  session closed
Nov 10  Nov 9 08:14:27 EST5EDT 2010 on tty .
Nov 10  Oct 19 02:14:21 EST5EDT 2010 on pts/tk .
Nov 10  afrtetryytr
Nov 10  session closed
Nov 10  Nov 10 03:21:04 EST5EDT 2010 
Dec  8   Nov 10 05:03:02 EST5EDT 2010

i have written a code for fatch the line no
Code:
Max_LIneNo=`grep -n "Nov 10" purge_exp1.txt | cut -f1 -d: | tail -1

that will give last line no number.
For above example it gives me out put 7

but i need to match only starting 2 words only
so my output should be 6

so where i could make change to get the output 6

please Help me

thanx in advance

Last edited by Yogesh Sawant; 02-01-2011 at 06:23 AM.. Reason: added code tags
# 2  
Old 02-01-2011
Try like this,
Code:
Max_LIneNo=`grep -n "^Nov 10" purge_exp1.txt | cut -f1 -d: | tail -1`

OR
Code:
awk '/^Nov 10/{i=NR} END {print i}' purge_exp1.txt

This User Gave Thanks to pravin27 For This Post:
# 3  
Old 02-01-2011
try:
Code:
grep -wn "^Nov 10" purge_exp1.txt | cut -f1 -d: | tail -1

or:
Code:
awk '/^Nov 10/{v=NR}END{print v}'

This User Gave Thanks to yinyuemi For This Post:
# 4  
Old 02-01-2011
hay guys thanx a lot
all script run properly
@ yinyuemi - why you use -wn ? if we use -n it also working.


one more question
: which is fast awk or grep?
# 5  
Old 02-01-2011
grep -w :match the whole form word
like:
Code:
echo "1
11
111" |grep 1
1
11
111

Code:
echo "1
11
111" |grep -w 1
1

The second question:
it's hard to say which is faster, it's dependent on your files and your requirement. For your question here, awk would be faster, I guess.Smilie

Last edited by Yogesh Sawant; 02-01-2011 at 06:24 AM.. Reason: added code tags
# 6  
Old 02-01-2011
Hi guys there is problem again

Max_LIneNo=`grep -wn "^Dec 3" purge_exp1.txt | cut -f1 -d: | tail -1`

then it is not give any output
-------------------------------
Max_LIneNo=`grep -wn "^Dec 3" purge_exp1.txt | cut -f1 -d: | tail -1`

var5=`awk '/^Dec 3/{i=NR} END {print i}' purge_exp1.txt`

but when we write above two command them it will me the line no of Dec 30 instead of DEC 3.



---------- Post updated at 03:42 PM ---------- Previous update was at 03:35 PM ----------

Hi Guys
there is problem again

when i run this command
Max_LIneNo=`grep -wn "^Dec 3" purge_exp1.txt | cut -f1 -d: | tail -1`
it was not give any output to me

but when i run below two command
Max_LIneNo=`grep -n "^Dec 3" purge_exp1.txt | cut -f1 -d: | tail -1`
var5=`awk '/^Dec 3/{i=NR} END {print i}' purge_exp1.txt`

then it will give me line no of Dec 31 line instead of Dec 3
# 7  
Old 02-01-2011
Try this,
Code:
awk '$1FS$2 =="Nov 3" {i=NR} END {print i}' inputfile

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