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fetch last line no form file which is match with specific pattern by grep command

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Top Forums Shell Programming and Scripting fetch last line no form file which is match with specific pattern by grep command
# 8  
Old 02-01-2011
Hi pravin

Thanx a lot buddy

can you plz explain this portion of command

$1FS$2 =="Nov 3"

it is working Smilie
# 9  
Old 02-01-2011
Hi,
Code:
$1FS$2=="Nov 3"

$1 is the first field i.e Nov and $2 is second field i.e 3 and FS is field separator.
So, above condition will check $1FS$2 is equal to Nov 3 then assign record number to variable i. Once finished processing of input file , it will print value of i.
# 10  
Old 02-01-2011
one more doubt buddy

if i run this
var5=`awk '$1FS$2 =="Dec 2" {i=NR} END {print i}' input file` then it working fine

but if i run in this way

var="Dec 3"
var5=`awk '$1FS$2 =="$var" {i=NR} END {print i}' input file` then it is not giving any outputSmilie
# 11  
Old 02-01-2011
Use -v option with awk
Code:
var5=`awk -v var="Dec 3" '$1FS$2 ==var {i=NR} END {print i}' input file`

# 12  
Old 02-01-2011
there is problem pravin

Hi

my code type is this in var3 i calulate date

var3=$Month1" "$day # var3=Dec 3

Max_LIneNo=`awk -v var="$var3" '$1FS$2 ==$var {i=NR} END {print i}' input File`

but it throw error "it is not correct."
# 13  
Old 02-01-2011
remove $ ... Please check post #11
Code:
Max_LIneNo=`awk -v var="$var3" '$1FS$2 ==$var {i=NR} END {print i}' input File`

This User Gave Thanks to pravin27 For This Post:
Himanshu_soni
# 14  
Old 02-01-2011
thanx buddy
you helped me alotSmilie
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