Parsing delimited file


 
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# 1  
Old 01-28-2011
Parsing delimited file

I'll have a file with ever changing lengths depending on the report. Right now it is stored by : delimiter. My question is how do I parse through this b/c it will be changing lengths each time.

Example:
Code:
1:2:3:4:5
1:2:3:4:5:6:7:8:9
1:2:3

I want to take each one and place in newline for further work.

Output desired:
Code:
1
2
3
4
5

1
2
3
4
5
6
7
8
9

1
2
3

Any help is appreciated. Thanks!

Last edited by radoulov; 01-28-2011 at 12:46 PM.. Reason: Code tags, please!
# 2  
Old 01-28-2011
Awk
Code:
cat file | awk -F : '
{  for (i=1;i<=NF; i++) {
        print $i
        }
   print ""
}'

ksh, bash, dash, ...
Code:
oifs="$IFS"
cat file | while read line
do
        IFS=":"
        for fld in $line
        do
                echo "$fld"
        done
        IFS="$oifs"
        echo
done

This User Gave Thanks to kshji For This Post:
# 3  
Old 01-28-2011
How about:
Code:
sed -e 's/$/\n/g' -e 's/:/\n/g' infile

This User Gave Thanks to citaylor For This Post:
# 4  
Old 01-28-2011
Fantastic. Thank you both. I came up with another....

tr -s ':' '\n' < infile
# 5  
Old 01-28-2011
Quote:
Originally Posted by mhuffs90171
tr -s ':' '\n' < infile
That doesnt seem to leave the double newline between records
# 6  
Old 01-29-2011
Code:
awk '$1=$1' FS=":" OFS="\n" ORS="\n\n" infile

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