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grep-awk one liner help

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# 1  
Old 01-28-2011
grep-awk one liner help
Hi guys, I'm trying to create a one line command that does the following.

I will post my command first so you can get the idea better:
Code:
ls -larht | awk '{print $4}' | uniq | xargs grep *

__________
Code:
ls -larht | awk '{print $4}' | uniq

This will post the name of the groups of each file inside a folder(without repeating).

Then I need to search those groupnames inside the files using grep.
Code:
[erickramirez@sdevgos01 ~/prueba]$ ls -larht
total 12K
-rw-r--r-- 1 erickramirez ccusers   46 Jan 28 08:28 1
-rw-r--r-- 1 erickramirez ccusers   78 Jan 28 08:28 2

[erickramirez@sdevgos01 ~/prueba]$ ls -larht | awk '{print $4}' | uniq

ccusers

## Now I want to search "ccusers" inside each file on the directory
Code:
[erickramirez@sdevgos01 ~/prueba]$ ls -larht | awk '{print $4}' | uniq | xargs grep *
grep: ccusers: No such file or directory

It's taking the result of the last command as the second argument (path) instead of the keyword. Please help! Smilie
Last edited by Franklin52; 01-28-2011 at 07:35 AM.. Reason: Please use code tags
# 2  
Old 01-28-2011
This perhaps?
Code:
ls -larht | awk '{print $4}' | uniq | sed 's/  */|/g' | xargs -I{} grep -E {} *

This User Gave Thanks to Scrutinizer For This Post:
erick_tuk
# 3  
Old 01-28-2011
Thanks a lot! really helpfull
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