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Replace with a variable in sed command

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# 1  
Old 01-05-2011
Replace with a variable in sed command
Hello,

I have this command and it works fine.
My question is that how can we replace the N by a variable, to print for instance a big number of lines. It means if I want 100 lines after an expression, to not put "N" 100 times in the sed.



Code:
$ sed -n '/aaa/{n;N;N;s/[ \n]//g;s/;/; /g;p;}' ttt2123 $ cat ttt20aaa12345678910
Thx & Regs,
Rany.
# 2  
Old 01-05-2011
On linux
Code:
sed -n '/aaa/,+100p' ttt2123

OR
Code:
a=100
sed -n '/aaa/,+${a}p' ttt2123

will print next 100 lines after pattern "aaa" match.
OR use awk to get same output:
Code:
awk '/aaa/{nr=NR}{if(nr && NR<nr+100) print}' ORS=" " ttt2123

OR
Code:
awk '/aaa/{nr=NR}{if(nr && NR<nr+a) print}' a=100 ORS=" " ttt2123

Last edited by anurag.singh; 01-05-2011 at 07:45 AM..
# 3  
Old 01-05-2011
ok, thx Singh
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