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How to print column based on row number

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# 1  
Old 12-31-2010
How to print column based on row number
Hi,
I want to print column value based on row number say multiple of 8.

Input file:
Code:
line 1 67  34
line 2 45  57
. . .
. . . 
line 8 12  46
. . .
. . .
line 16 24  90
. . .
. . .
line 24 49  67

Output
Code:
46
90
67

I tried
Code:
"for ((i = 1; i<=3; i++)) 
do
b=$(echo "scale=2;($i*8)"| bc)
awk "NR==$b {print $2}" input file>> output file
done"

But it prints both the columns. I want to print only 2nd column.
Please help



Moderator's Comments:
Mod Comment Please use code tags when posting data and code samples, thank you.
Last edited by Franklin52; 12-31-2010 at 07:21 AM..
# 2  
Old 12-31-2010
Use single quotes instead of double quotes:
Code:
awk "NR==$b"' {print $2}' ....

Otherwise $2 gets expanded by the shell.

You could do this all in one awk like this:
Code:
awk '!(NR%8){print $2}' infile

# 3  
Old 12-31-2010
I works. Thank you
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