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Format output from the file to extract "date" section

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# 1  
Old 12-16-2010
Format output from the file to extract "date" section
Hello Team ,

I have to extract date section from the below file output. The output of the file is as shown below.

Quote:
bash-3.00$ grep -i outofmemory SystemOut.log_bak14122010
[12/14/10 14:43:03:732 CET] 00000041 servlet E com.ibm.ws.webcontainer.servlet.ServletWrapper service SRVE0068E: Uncaught exception created in one of the service methods of the servlet springDispatcherServlet in application ccrtool. Exception created : org.springframework.web.util.NestedServletException: Handler processing failed; nested exception is java.lang.OutOfMemoryError: Java heap space
Caused by: java.lang.OutOfMemoryError: Java heap space
[12/14/10 14:46:15:086 CET] 00000041 webapp E com.ibm.ws.webcontainer.webapp.WebApp logServletError SRVE0293E: [Servlet Error]-[springDispatcherServlet]: java.lang.OutOfMemoryError: Java heap space
bash-3.00$
I have to extract the "[12/14/10 14:43:03:732 CET]" this section from the above output of the file. can anyone please let me know how can we acheive this?
# 2  
Old 12-16-2010
Code:
awk 'NR==1{print $1,$2,$3}' SystemOut.log_bak14122010

# 3  
Old 12-16-2010
You could leave out the grep with this:
Code:
$> sed -n '/OutOfMemory/ {s/\].*/]/p}' SystemOut.log_bak14122010
[12/14/10 14:43:03:732 CET]
[12/14/10 14:46:15:086 CET]

This is done with GNU sed. If it wont work with your version of sed, you might have to write it like:
Code:
$> sed -n '
/OutOfMemory/
{
s/\].*/]/p
}
' SystemOut.log_bak14122010

# 4  
Old 12-16-2010
Hello cabrao,

I have ran the command and i am getting following error in the output

Code:
bash-3.00$ awk 'NR==1{print $1,$2,$3}' SystemOut.log_bak14122010
************ Start Display
awk: record `[12/14/10 15:54:22:9...' too long
 record number 6014

---------- Post updated at 09:58 AM ---------- Previous update was at 09:56 AM ----------

Hello zaxxon,

I have ran the command and i am getting following output.

Code:
bash-3.00$ sed -n '/OutOfMemory/ {s/\].*/]/p}' SystemOut.log_bak14122010
sed: command garbled: /OutOfMemory/ {s/\].*/]/p}
bash-3.00$

# 5  
Old 12-16-2010
I have written, that if the 1st command does not work, you might try the 2nd command I posted. That's due to different versions of sed.
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