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Passing Variable to Regular Expression

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# 1  
Old 12-14-2010
CPU & Memory Passing Variable to Regular Expression
Hi All,

Below is a sample code:
Code:
        print "Enter the Name:  ";
        my $Name = <>;
        print "Word is $Name";

        open (FH,"AIDNameList.txt");
        while (<FH>)
        {
                my $line;
                print "Word is $Name";
                for $line(<FH>)
                {
                        for ($line =~ /$NameAid/g )                        {
                                print $line;
                        }
                }
        }
        close FH;

I need to search for the user entered value in Variable $Name and search in each line of the file "AIDNameList.txt". I tried many ways but cudnot find how to give the word in the for loop.

Could some one help me out..

Thanks in advance
JS
Last edited by Franklin52; 12-14-2010 at 08:38 AM.. Reason: Please use code tags, thank you
# 2  
Old 12-14-2010
Code:
 
cat AIDNameList.txt | grep "${Name}Aid" | while read line
do
     print $line;
done

This User Gave Thanks to anurag.singh For This Post:
jisha
# 3  
Old 12-14-2010
Much simpler Perl version
Code:
print "Enter the Name:  ";
my $Name = <>;
print "Word is $Name";

open my $FH, '<', 'AIDNameList.txt' or die "Can't read AIDNameList: $!";
print grep { /$Name/ } <$FH>;
close $FH;

This User Gave Thanks to pludi For This Post:
jisha
# 4  
Old 12-16-2010
Thank you all for the reply ... but somehow it is not working .. I am trying to tune it .. Smilie

---------- Post updated at 03:02 PM ---------- Previous update was at 12:59 PM ----------

Quote:
Originally Posted by pludi
Much simpler Perl version
Code:
print "Enter the Name:  ";
my $Name = <>;
print "Word is $Name";

open my $FH, '<', 'AIDNameList.txt' or die "Can't read AIDNameList: $!";
print grep { /$Name/ } <$FH>;
close $FH;

I tried but still i dont get the output. the grep command is not taking the value in $Name. I need to search for the value in the variable $Name. Smilie
# 5  
Old 12-16-2010
Can u post sample input string and existence of the same in input file to get exact idea on your problem?
R0H0N
# 6  
Old 12-16-2010
My sample AIDNameList.txt file is as below :
_________________________________
name1 emailid1
name2 emailid2
name3 emaild3

My program is to take input value from used (say "name2") and search for this in the file "AIDNameList.txt" and print the whole line "name2 emailid2
"

I need "only" that particular line to be printed.
# 7  
Old 12-16-2010
Sorry, my bad, you'll have to chomp the input, otherwise it'll include the newline character in the search:
Code:
print "Enter the Name:  ";
my $Name = <>;
chomp $Name;
print "Word is $Name";

open my $FH, '<', 'AIDNameList.txt' or die "Can't read AIDNameList: $!";
print grep { /$Name/ } <$FH>;
close $FH;

Besides, what's wrong with using a regular grep?
This User Gave Thanks to pludi For This Post:
jisha
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