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# 1  
Old 12-06-2010
Question sed regular expression help
please consider this:

Code:
echo "11111*X*005010X279~ST*270*1111111*005010X279~BHT*0011*11" |  sed 's/.*\(005010X(\d)(\d)(\d)[A-Za-z]*\).*$/\1/'

i'm searching for first occurrence of 005010X [digit] [digit] [digit] [optional letter] while leaving rest of characters out.

Smilie

any tips? thnx in advance guys.
# 2  
Old 12-06-2010
Code:
echo "11111*X*005010X279~ST*270*1111111*005010X279~BHT*0011*11" | sed 's/.*\(005010X[0-9]\{3\}[A-Za-z]\).*$/\1/'

gave

005010X279

is this what you looking for?
Last edited by EAGL€; 12-06-2010 at 05:50 PM.. Reason: removed the star after [A-Za-z]
This User Gave Thanks to EAGL€ For This Post:
grep01
# 3  
Old 12-06-2010
Computer
thnx so much!,

for some reason i needed to adjust it to this:
Code:
echo "11111*X*005010X279E~ST*270*1111111*005010X279~BHT*0011*11" | sed 's/.*\(005010X[0-9][0-9][0-9][A-Za-z]\).*$/\1/'

# 4  
Old 12-07-2010
What OS are you using?
# 5  
Old 12-07-2010
>What OS are you using?
aix 5.3
using ksh
# 6  
Old 12-07-2010
That should not make a difference then. Are you sure it makes a difference?

But anyway, the last letter is optional, so neither statement is according to specification. The trouble is that you can't really get it to work like this, because of .* at the beginning which becomes too greedy and so the second pattern gets matched..
Code:
echo "11111*X*005010X279X~ST*270*1111111*005010X279~BHT*0011*11" | sed 's/[*~]/\n/g' | sed -n '/005010X[0-9]\{3\}[A-Za-z]\{0,1\}/{p;q;}'

or
Code:
echo "11111*X*005010X279X~ST*270*1111111*005010X279~BHT*0011*11" | awk -F'~' '/005010X[0-9][0-9][0-9][A-Za-z]?/{print $1;exit}' RS=\*

Last edited by Scrutinizer; 12-07-2010 at 04:58 AM..
# 7  
Old 12-07-2010
Hello Scrutinizer

in following sed command
Quote:
sed -n '/005010X[0-9]\{3\}[A-Za-z]\{0,1\}/{p;q;}
Could you pls. explain what {p;q;} does.

thanks
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